3.153 \(\int \tan ^p(a+b \log (x)) \, dx\)

Optimal. Leaf size=142 \[ x \left (1-e^{2 i a} x^{2 i b}\right )^{-p} \left (\frac {i \left (1-e^{2 i a} x^{2 i b}\right )}{1+e^{2 i a} x^{2 i b}}\right )^p \left (1+e^{2 i a} x^{2 i b}\right )^p F_1\left (-\frac {i}{2 b};-p,p;1-\frac {i}{2 b};e^{2 i a} x^{2 i b},-e^{2 i a} x^{2 i b}\right ) \]

[Out]

x*(I*(1-exp(2*I*a)*x^(2*I*b))/(1+exp(2*I*a)*x^(2*I*b)))^p*(1+exp(2*I*a)*x^(2*I*b))^p*AppellF1(-1/2*I/b,-p,p,1-
1/2*I/b,exp(2*I*a)*x^(2*I*b),-exp(2*I*a)*x^(2*I*b))/((1-exp(2*I*a)*x^(2*I*b))^p)

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Rubi [F]  time = 0.02, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \tan ^p(a+b \log (x)) \, dx \]

Verification is Not applicable to the result.

[In]

Int[Tan[a + b*Log[x]]^p,x]

[Out]

Defer[Int][Tan[a + b*Log[x]]^p, x]

Rubi steps

\begin {align*} \int \tan ^p(a+b \log (x)) \, dx &=\int \tan ^p(a+b \log (x)) \, dx\\ \end {align*}

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Mathematica [B]  time = 0.69, size = 330, normalized size = 2.32 \[ \frac {(2 b-i) x \left (-\frac {i \left (-1+e^{2 i a} x^{2 i b}\right )}{1+e^{2 i a} x^{2 i b}}\right )^p F_1\left (-\frac {i}{2 b};-p,p;1-\frac {i}{2 b};e^{2 i a} x^{2 i b},-e^{2 i a} x^{2 i b}\right )}{-2 e^{2 i a} b p x^{2 i b} F_1\left (1-\frac {i}{2 b};1-p,p;2-\frac {i}{2 b};e^{2 i a} x^{2 i b},-e^{2 i a} x^{2 i b}\right )-2 e^{2 i a} b p x^{2 i b} F_1\left (1-\frac {i}{2 b};-p,p+1;2-\frac {i}{2 b};e^{2 i a} x^{2 i b},-e^{2 i a} x^{2 i b}\right )+(2 b-i) F_1\left (-\frac {i}{2 b};-p,p;1-\frac {i}{2 b};e^{2 i a} x^{2 i b},-e^{2 i a} x^{2 i b}\right )} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[Tan[a + b*Log[x]]^p,x]

[Out]

((-I + 2*b)*x*(((-I)*(-1 + E^((2*I)*a)*x^((2*I)*b)))/(1 + E^((2*I)*a)*x^((2*I)*b)))^p*AppellF1[(-1/2*I)/b, -p,
 p, 1 - (I/2)/b, E^((2*I)*a)*x^((2*I)*b), -(E^((2*I)*a)*x^((2*I)*b))])/(-2*b*E^((2*I)*a)*p*x^((2*I)*b)*AppellF
1[1 - (I/2)/b, 1 - p, p, 2 - (I/2)/b, E^((2*I)*a)*x^((2*I)*b), -(E^((2*I)*a)*x^((2*I)*b))] - 2*b*E^((2*I)*a)*p
*x^((2*I)*b)*AppellF1[1 - (I/2)/b, -p, 1 + p, 2 - (I/2)/b, E^((2*I)*a)*x^((2*I)*b), -(E^((2*I)*a)*x^((2*I)*b))
] + (-I + 2*b)*AppellF1[(-1/2*I)/b, -p, p, 1 - (I/2)/b, E^((2*I)*a)*x^((2*I)*b), -(E^((2*I)*a)*x^((2*I)*b))])

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fricas [F]  time = 0.46, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\tan \left (b \log \relax (x) + a\right )^{p}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(a+b*log(x))^p,x, algorithm="fricas")

[Out]

integral(tan(b*log(x) + a)^p, x)

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(a+b*log(x))^p,x, algorithm="giac")

[Out]

Timed out

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maple [F]  time = 0.33, size = 0, normalized size = 0.00 \[ \int \tan ^{p}\left (a +b \ln \relax (x )\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tan(a+b*ln(x))^p,x)

[Out]

int(tan(a+b*ln(x))^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \tan \left (b \log \relax (x) + a\right )^{p}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(a+b*log(x))^p,x, algorithm="maxima")

[Out]

integrate(tan(b*log(x) + a)^p, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\mathrm {tan}\left (a+b\,\ln \relax (x)\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tan(a + b*log(x))^p,x)

[Out]

int(tan(a + b*log(x))^p, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \tan ^{p}{\left (a + b \log {\relax (x )} \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(a+b*ln(x))**p,x)

[Out]

Integral(tan(a + b*log(x))**p, x)

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